-q^2-2q+195=0

Solution for -q^2-2q+195=0 equation:

-q^2-2q+195=0

We add all the numbers together, and all the variables

-1q^2-2q+195=0

a = -1; b = -2; c = +195;
Δ = b2-4ac
Δ = -22-4·(-1)·195
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-28}{2*-1}=\frac{-26}{-2}
=+13
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+28}{2*-1}=\frac{30}{-2}
=-15
$